Find words that can be formed by characters

You have given an array of words and a string S.

Given an integer k and a string str consisting of lowercase English alphabets, the task is to count how many k-character words with or without meaning can be formed from the characters of str when repetition is not allowed. Approach: Count the number of distinct characters in str and store it in cnt , now the task is to arrange k characters out of cnt characters i. Time Complexity: O n , where n is the length of the given string. Auxiliary Space: O 1. Skip to content. Change Language.

Find words that can be formed by characters

In this problem, we are given two inputs: an array of strings called words and a single string called chars. Our task is to determine which strings in the words array are "good". A "good" string is one that can be completely formed using the characters in chars. Each character in chars may only be used once when forming a word. After identifying all the "good" strings, we must calculate the sum of their lengths and return that sum as the result. The lengths of "cat" and "hat" are 3 and 3, respectively, so the sum is 6. The goal of the problem is to implement a function that can do this calculation for any given words and chars. Count Characters in chars : We first count the frequency of each character in the string chars. This helps us know how many times we can use a particular character while forming words. Iterate Over words : Next, we loop through each string in words and count the frequency of each character in the current string w. Check if a Word Can be Formed: To determine if a word is "good", we compare character frequencies of the current word with those in chars. If for each character in the word, the count in chars is greater than or equal to the count in the word, the word is "good". Calculate and Sum Lengths: For each "good" string found, we add its length to a running total, ans. Return the Result: Once all words have been checked, return the accumulated sum of lengths. The beauty of this approach lies in the efficient use of character counting, which allows us to verify if a word can be formed without having to repeatedly search for characters in chars.

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A simple solution is to try all characters one by one. If all characters satisfy this condition, return true. Else return false. An efficient solution is to create a frequency array of length Number of possible characters and initialize it to 0. Skip to content.

Given a dictionary, a method to do lookup in dictionary and a M x N board where every cell has one character. Find all possible words that can be formed by a sequence of adjacent characters. Note that we can move to any of 8 adjacent characters, but a word should not have multiple instances of same cell. The idea is to consider every character as a starting character and find all words starting with it. All words starting from a character can be found using Depth First Traversal. We do depth-first traversal starting from every cell. We keep track of visited cells to make sure that a cell is considered only once in a word. Note that the above solution may print the same word multiple times. To avoid this, we can use hashing to keep track of all printed words. Instead of generating all strings from the grid and the checking whether it exists in dictionary or not , we can simply run a DFS on all words present in dictionary and check whether we can make that word from grid or not.

Find words that can be formed by characters

In this problem, we are given two inputs: an array of strings called words and a single string called chars. Our task is to determine which strings in the words array are "good". A "good" string is one that can be completely formed using the characters in chars. Each character in chars may only be used once when forming a word. After identifying all the "good" strings, we must calculate the sum of their lengths and return that sum as the result. The lengths of "cat" and "hat" are 3 and 3, respectively, so the sum is 6. The goal of the problem is to implement a function that can do this calculation for any given words and chars. Count Characters in chars : We first count the frequency of each character in the string chars. This helps us know how many times we can use a particular character while forming words. Iterate Over words : Next, we loop through each string in words and count the frequency of each character in the current string w.

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Given a dictionary and a character array, print all valid words that are possible using characters from the array.

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