Leetcode 2534

There are 5 states involved. State can be transformed by folds, etc, elegantly although perhaps not with great performance.

There is a long and thin painting that can be represented by a number line. Painting the same area multiple times will create an uneven painting so you only want to paint each area of the painting at most once. Create a boolean array to store whether each block has been painted. We can check each of these blocks, painting the unpainted ones we also keep count of how many blocks we paint because that's what the question asks for. In the worst case, we have to check every block on every day.

Leetcode 2534

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In this problem, there are n persons who want to enter or exit through a door. Each person can enter or exit through the door once, taking one second. We are given a non-decreasing integer array arrival of size n , where arrival[i] is the arrival time of the i th person at the door. Also, there is an array state of size n , where state[i] is 0 if person i wants to enter through the door or 1 if they want to exit through the door. The main goal is to find an array answer of size n where answer[i] is the second at which the i th person crosses the door, considering various rules regarding entering and exiting the door.

In this problem, there are n persons who want to enter or exit through a door. Each person can enter or exit through the door once, taking one second. We are given a non-decreasing integer array arrival of size n , where arrival[i] is the arrival time of the i th person at the door. Also, there is an array state of size n , where state[i] is 0 if person i wants to enter through the door or 1 if they want to exit through the door. The main goal is to find an array answer of size n where answer[i] is the second at which the i th person crosses the door, considering various rules regarding entering and exiting the door. We can use two pointers approach for solving this problem. First, we can create two lists, one for the entering persons and one for the exiting persons, and initialize pointers at the beginning of those lists. Next, we can iterate until both pointers reach the end of their respective lists. Finally, we can follow the rules stated in the problem description for entering and exiting persons and update the answer array accordingly. These solutions follow the same approach mentioned above and can be used for the respective programming languages.

Leetcode 2534

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